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Fe8

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[(tacn)₆Fe₈O₂(OH)₁₂]⁸⁺[Br₈.9H₂O]^8-

where tacn (pronounce tack-en) stands for 1,4,7-Triazacyclononane and is the distorted ring with three N H units (small, gray - tiny, white). Carbon atoms are (small, white) and come in twos, sharing a double bond. Fe is (large, gray) and O is (small, black). All Fe are Fe³⁺, high spin state, {$S=\frac 5 2$}. The total effective spin, in the depicted ground state configuration is therefore {$S_{tot}=(6-2)\frac 5 2 = 10$}

For µSR purposes it does have three unsaturated bonds per tacn, i.e. eighteen in all.

Certain to produce radicals: by eye I would count the following isomers:

• four tacn are attached to Fe³⁺, each with two equivalent (?) bonds (total of 8) plus one inequivalent (total of 4)
• the other two tacn have two equivalent (?) bonds (total of 4) and one inequivalent (total of 2)

If the symmetry is lower than I assumed there are certainly two mirror planes (horizontal and vertical, so that at most there are six isomes with multiplicity: 4 4 4 2 2 2

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