Derivation of Ginzburg Landau equations
This section may be skipped, at least at first reading.
Following the general GL theory for inhomogeneous orderer parameters {$\psi$} (complex) in the presence of magnetic field, {$\mathbf B = \boldsymbol \nabla\times\mathbf A=\mu_0(\mathbf H + \mathbf M)$}, written in terms of the vector potential {$\mathbf A$}, the Gibbs free energy is
{$$
G_s(T,H) = G_n(T,H) +\int d\mathbf r g_s(T;\mathbf r)
$$}
The Gibbs free energy density {$g_s(T;\mathbf r)$}, contains two modifications with respect to the {$H=0$} case. We must apply the minimal substitution, {$-i\hbar\boldsymbol\nabla\rightarrow-i\hbar\boldsymbol\nabla-q\mathbf A$} to the gradient term (and {$q$} turns out to be equal to {$-2e$} for the Cooper pair). We must also add the density of work done by the field, the opposite of the corresponding energy density {$-B^2/2\mu_0$}. For ease of notation we rename {$a$} the whole quadratic coefficient, normally {$a(T_c-T)$}. We obtain
{$$
g_s(T;\mathbf r) = a|\psi|^2+\frac b 2 |\psi|^4 + \frac 1{2m^*}|(-i\hbar\boldsymbol\nabla-q\mathbf A)\psi|^2 + \frac 1 {2\mu_0}|\boldsymbol\nabla \times A|^2
$$}
The variational principle must be applied for three independent parameters:
- {$\psi^*\rightarrow\psi^*+\delta\psi^*$}, that yields the Ginzburg-Landau equation for the complex order parameter {$\psi$},
- {$\psi\rightarrow\psi+\delta\psi$}, that yields the conjugate equation (thus we may skip it)
- {$\mathbf A \rightarrow \mathbf A + \delta \mathbf A$}, that yields the equation for the source of the magnetization, the current density {$J_{ext}+J_s$}; with boundary conditions on an infinite superconducting cylinder {$J_s$}, since {$J_{ext}=0$} in the volume.
We require that {$\delta\int d\mathbf r g_s(T;\mathbf r)=0$} for each independent variation. As usual the trick is to write the integral kernel as a coefficient times the selected variation. Then the integral will always vanish, for any variation, if and only if the coefficient vanishes, which yields the GL equation.
For the order parameter, the variation of the density is {$\delta g_s = g_s(\psi^*+\delta\psi^*)-g_s(\psi^*)$}, i.e.
{$$
\delta g_s = \left[a\psi + b |\psi|^2\psi + \frac 1 {2m^*}(iq\hbar\boldsymbol\nabla \psi\cdot \mathbf A+ q^2 A^2 \psi)\right]\delta \psi^*
+ \frac 1 {2m^*} (\hbar^2\boldsymbol\nabla \psi-iq\hbar\mathbf A \psi)\cdot\boldsymbol\nabla \delta\psi^*
$$}.
The second part of the RHS must be integrated by parts, with {$\int d\mathbf r\, \mathbf g \cdot\boldsymbol\nabla f=\int_\Sigma \,f\mathbf g \cdot d\mathbf \sigma - \int d\mathbf r f \boldsymbol\nabla\cdot\mathbf g$}. The surface integral on the boundary of the superconductor vanishes since the order parameter there, hence we can rewrite
{$$
\delta g_s = \left(a\psi + b |\psi|^2\psi + \frac 1 {2m^*}\left[-\hbar^2\nabla^2 \psi +iq\hbar(\boldsymbol\nabla \psi\cdot \mathbf A+ \boldsymbol\nabla \cdot\mathbf A\psi) +q^2 A^2 \psi\right]\right)\delta \psi^*
$$}.
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